(4/(x^2-5x))-(2/x)=(2/(x-5))

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Solution for (4/(x^2-5x))-(2/x)=(2/(x-5)) equation:


D( x )

x-5 = 0

x = 0

x^2-(5*x) = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

x^2-(5*x) = 0

x^2-(5*x) = 0

x^2-5*x = 0

x^2-5*x = 0

DELTA = (-5)^2-(0*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+5)/(1*2) or x = (5-25^(1/2))/(1*2)

x = 5 or x = 0

x in (-oo:0) U (0:5) U (5:+oo)

4/(x^2-(5*x))-(2/x) = 2/(x-5) // - 2/(x-5)

4/(x^2-(5*x))-(2/(x-5))-(2/x) = 0

4/(x^2-5*x)-2*(x-5)^-1-2*x^-1 = 0

4/(x^2-5*x)-2/(x-5)-2/x = 0

x^2-5*x = 0

x^2-5*x = 0

x*(x-5) = 0

x-5 = 0 // + 5

x = 5

x*(x-5) = 0

4/(x*(x-5))-2/(x-5)-2/x = 0

4/(x*(x-5))+(-2*x)/(x*(x-5))+(-2*(x-5))/(x*(x-5)) = 0

4-2*(x-5)-2*x = 0

4-2*x-2*x+10 = 0

14-4*x = 0

(14-4*x)/(x*(x-5)) = 0

(14-4*x)/(x*(x-5)) = 0 // * x*(x-5)

14-4*x = 0

14-4*x = 0 // - 14

-4*x = -14 // : -4

x = -14/(-4)

x = 7/2

x = 7/2

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